0=-4.9t^2+14t-8

Solution for 0=-4.9t^2+14t-8 equation:

0=-4.9t^2+14t-8

We move all terms to the left:

0-(-4.9t^2+14t-8)=0

We add all the numbers together, and all the variables

-(-4.9t^2+14t-8)=0

We get rid of parentheses

4.9t^2-14t+8=0

a = 4.9; b = -14; c = +8;
Δ = b2-4ac
Δ = -142-4·4.9·8
Δ = 39.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-\sqrt{39.2}}{2*4.9}=\frac{14-\sqrt{39.2}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+\sqrt{39.2}}{2*4.9}=\frac{14+\sqrt{39.2}}{9.8}
$